[Rd] How does .Fortran "dqrls" work?

[yangleicq]

Hi, all.
I want to write some functions like glm() so i studied it.
In glm.fit(), it calls a fortran subroutine named  "dqrfit" to compute least
squares solutions
 to the system
              x * b = y

To learn how "dqrfit" works, I just follow how glm() calls "dqrfit" by my
own example, my codes are given below:

>  qr <-
> matrix(c(4.17,5.58,5.18,6.11,4.50,4.61,5.17,4.53,5.33,5.14,2.3,1.7,1.3,1.7,1.7,1.6,1,1.7,1.7,1.7),ncol=2)
> qr 
      [,1] [,2]
 [1,] 4.17  2.3
 [2,] 5.58  1.7
 [3,] 5.18  1.3
 [4,] 6.11  1.7
 [5,] 4.50  1.7
 [6,] 4.61  1.6
 [7,] 5.17  1.0
 [8,] 4.53  1.7
 [9,] 5.33  1.7
[10,] 5.14  1.7
> n=10
>  p=2
>  y <- c(4.81,4.17,4.41,3.59,5.87,3.83,6.03,4.89,4.32,4.69)
>  ny=1L
>  tol=1e-07
>  coefficients=double(p)
>  residuals=double(n)
>  effects=double(n)
>  rank=integer(1L)
>  pivot=1:n
>  qraux=double(n)
>  work=double(2*n)
>  
>  
>  
>  fittt<-.Fortran("dqrls", qr =qr, n = n, 
+                 p = p, y = y, ny = ny, tol = tol,
coefficients=coefficients,
+                 residuals = residuals, effects = effects, 
+                 rank = rank, pivot = pivot, qraux = qraux, 
+                 work = work, PACKAGE = "base")
>  
>  fittt$coefficients
[1] 0 0

but when i use lm() which also calls "dqrls" internally to fit this model,
it gives reasonable result.

> lm(y~qr)

Call:
lm(formula = y ~ qr)

Coefficients:
(Intercept)          qr1          qr2  
    11.1766      -0.8833      -1.2628  


when I change the coefficients to be c(1,1), the output from "dqrls", 
fittt$coefficients also equals to c(1,1). That means the  .Fortran("dqrls",
qr=qr,n=n,p=p,...) did nothing to the coefficients! I don't know why, is
there anything I did wrong or missed?  How can I get the result from "dqrls"
as what lm() or glm() gets from "dqrls"?

Thanks in advance. Best Regards.



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