[Rd] Evaluation puzzle

[Terry Therneau]

The survexp function can fail when called from another function.  The "why" of
this has me baffled, however.

Here is a simple test case, using a very stripped down version of survexp:

survexp.test <- function(formula, data,
        weights, subset, na.action, rmap, 
        times,  cohort=TRUE,  conditional=FALSE,
        ratetable=survexp.us, scale=1, npoints, se.fit,
        model=FALSE, x=FALSE, y=FALSE) {
    call <- match.call()
    m <- match.call(expand.dots=FALSE)
        
    # keep the first element (the call), and the following selected arguments
    m <- m[c(1, match(c('formula', 'data', 'weights', 'subset', 'na.action'),
                      names(m), nomatch=0))]
    m[[1]] <- as.name("model.frame")

    # Add in the ratetable variables
    varlist <- attr(ratetable, 'dimid')
    tform <- paste(deparse(formula), paste(varlist, collapse='+'), sep='+')
    m$formula <- tform

    print(m)
    print(ls(parent.frame()))
    mf <- eval(m, parent.frame())
    
    names(mf)
    }

Here is the test data

tdata <- data.frame(age= c(12, 24, 36)*365.25, sex=c(1,2,1),
                    year=as.Date('1953/03/10', '1960/02/23', '1978/09.22'))
tfun <- function(mydata) {
     zed <- 100 + (1:nrow(mydata)) * 20
     survexp.test(zed ~ 1, data=mydata)
     }

And the result of the exercise.

% R --vanilla
R version 2.11.0 (2010-04-22)

> library(survival)    # to pick up the survexp.us data
> tfun(tdata)
model.frame(formula = "zed ~ 1+age+sex+year", data = mydata)
[1] "mydata" "zed"   
Error in eval(expr, envir, enclos) : object 'zed' not found

-----
 Eval is being called with the expression shown and an environment that 
contains the relevant variables in that expression: zed and mydata.  Yet it
fails to find the variable zed.

 I don't see anything relevant in the manual pages for either eval or
model.frame.  I suspect that there is an invisible, undocumented, magic
argument somewhere.  


My second problem is a puzzler:

> options(error=recover)
> tfun(tdata)
model.frame(formula = "zed ~ 1+age+sex+year", data = mydata)
[1] "mydata" "zed"   
Error in eval(expr, envir, enclos) : object 'zed' not found

Enter a frame number, or 0 to exit   

1: tfun(tdata)
2: survexp.test(zed ~ 1, data = mydata)
3: eval(m, parent.frame())
4: eval(expr, envir, enclos)
5: model.frame(formula = "zed ~ 1+age+sex+year", data = mydata)
6: model.frame.default(formula = "zed ~ 1+age+sex+year", data = mydata)
7: eval(predvars, data, env)
8: eval(expr, envir, enclos)

Selection: 2
Called from: model.frame.default(formula = "zed ~ 1+age+sex+year", data = mydata)


 Why does selecting "2" result in going to frame "6"?

Terry Therneau