[Rd] Why is there no c.factor?

[Hadley Wickham]

On Thu, Feb 4, 2010 at 12:03 PM, Hadley Wickham <hadley at rice.edu> wrote:
>> I'd propose the following: If the sets of levels of all arguments are the
>> same, then c.factor() would return a factor with the common set of levels;
>> if the sets of levels differ, then, as Hadley suggests, the level-set of the
>> result would be the union of sets of levels of the arguments, but a warning
>> would be issued.
>
> I like this compromise (as long as there was an argument to suppress
> the warning)

If I provided code to do this, along with the warnings for ordered
factors and using the optimisation suggested by Matthew, is there any
member of R core would be interested in sponsoring it?

Hadley

-- 
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