[Rd] Question R's parser : - parsing "x=\n 1"
Simon Urbanek
simon.urbanek at r-project.org
Wed Nov 25 07:09:51 CET 2009
On Nov 25, 2009, at 1:03 AM, Saptarshi Guha wrote:
> Hello
> I was reading the source main/src/gram.y and had one question, how
> does R parse
>
> x =
> 1
>
> According the grammar:
>
> prog : END_OF_INPUT { return 0; }
> | '\n' { return xxvalue(NULL,2,NULL); }
> | expr_or_assign '\n' { return xxvalue($1,3,&@1); }
> | expr_or_assign ';' { return xxvalue($1,4,&@1); }
> | error { YYABORT; }
> ;
>
>
> So this should be of the 3rd form.
> Also, the expr_or_assign is of the 2nd form in
>
> expr_or_assign : expr { $$ = $1; }
> | equal_assign { $$ = $1; }
> ;
>
> where equal_assign is
>
> equal_assign : expr EQ_ASSIGN expr_or_assign { $$ =
> xxbinary($2,$1,$3); }
>
> When the parser sees 'x' and '=' it expects an expr_or_assign and we
> know it will receive an expr. However, the expr cannot be a new
> line(according to the defn of expr)
>
> So instead of an expr, the parse gets a newline and should fail.
> Q: So how does R parse this?
> I think it fails with a Parse_Incomplete and keeps on reading till EOF
> (or till an expression is complete).
> But this is not really an incomplete expression
It is. "x=" is incomplete -- try it in R and you'll see that you get a
continuation prompt because it's incomplete:
> x=
+ 1
Cheers,
S
> but if my
> interpretation is correct a syntax error, yet R parses it.
> So i understood something else or R's engine manages to do things
> differently
> Regards
> Saptarshi
>
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