[Rd] Accuracy (PR#13867)

Greg.Snow at imail.org Greg.Snow at imail.org
Wed Aug 5 01:30:35 CEST 2009


What research into this problem did you do that failed to turn up FAQ 7.31?

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Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.snow at imail.org
801.408.8111


> -----Original Message-----
> From: r-devel-bounces at r-project.org [mailto:r-devel-bounces at r-
> project.org] On Behalf Of luethman at student.ethz.ch
> Sent: Tuesday, August 04, 2009 8:25 AM
> To: r-devel at stat.math.ethz.ch
> Cc: R-bugs at r-project.org
> Subject: [Rd] Accuracy (PR#13867)
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> Full_Name: Manuel Luethi
> Version: 2.9.1
> OS: Windows XP
> Submission from: (NULL) (129.132.128.136)
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> Hi
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> I created the following vectors:
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> p_1=3Dc(0.2,0.2,0.2,0.2,0.1,0.25,0.4,0.1,0.25,0.4,0.1,0.25,0.4,0.1,0.25,0
> .4,0.2,0.5,0.8,0.2,0.5,0.8,0.2,0.5,0.8,0.2,0.5,0.8)
> p_2=3Dc(0,0,0,0,0.5,0.5,0.5,0.5,0.5,0.5,0.5,0.5,0.5,0.5,0.5,0.5,0.4,0.25,
> 0.1,0.4,0.25,0.1,0.4,0.25,0.1,0.4,0.25,0.1)
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> As these are probabilities, I calculated the remainder as
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> p_3=3D1-p_1-p_2
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> There the values which ought to be 0.1 were lateron not recognised by
> p_3=3D=3D0.1,
> but only if I used p_3 <=3D 0.1.
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> The full calculation is actually bigger but the core issue remains: I
> used
> values input by hand, built a difference and it was wrong.
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> I know that exactly the value 0.1 is one that can not be represented
> using
> binary rep. Maybe that's it, maybe not. Just wanted to let you know.
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> With kind regards
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> Manuel
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