[Rd] Floating point maths in R

Tom McCallum tom.mccallum at levelelimited.com
Sat Dec 9 14:29:01 CET 2006


Hi,

I am not sure if this is just me using R (R-2.3.1 and R-2.4.0) in the  
wrong way or if there is a more serious bug.  I was having problems  
getting some calculations to add up so I ran the following tests:

> (2.34567 - 2.00000) == 0.34567 <------- should be true
[1] FALSE
> (2.23-2.00) == 0.23 <------- should be true
[1] FALSE
> 4-2==2
[1] TRUE
> (4-2)==2
[1] TRUE
> (4.0-2)==2
[1] TRUE
> (4.0-2.0)==2
[1] TRUE
> (4.0-2.0)==2.0
[1] TRUE
> (4.2-2.2)==2.0
[1] TRUE
> (4.20-2.20)==2.00
[1] TRUE
> (4.23-2.23)==2.00  <------- should be true
[1] FALSE
> (4.230-2.230)==2.000 <------- should be true
[1] FALSE
> (4.230-2.230)==2.00 <------- should be true
[1] FALSE
> (4.230-2.23)==2.00 <------- should be true
[1] FALSE

I have tried these on both 64 and 32-bit machines.  Surely R should be  
able to do maths to 2 decimal places and be able to test these simple  
expressions?  The problem occurs as in the 16th decimal place junk is  
being placed by the FPU it seems.  I have also tried:

> (4.2300000000000000-2.230000000000000) == 2
[1] FALSE
> a <- (4.2300000000000000-2.230000000000000)
> a == 2
[1] FALSE
> (4.2300000000000000-2.230000000000000) == 2.0000000000000000
[1] FALSE
> (4.2300000000000000-2.230000000000000) == 2.0000000000000004 <-- correct  
> when add 16th decimal place to 4
[1] TRUE
> (4.2300000000000000-2.230000000000000) == 2.00000000000000043  <-- any  
> values after the 16th decimal place mean that the expression is true
[1] TRUE
> (4.2300000000000000-2.230000000000000) == 2.000000000000000435
[1] TRUE

Also :

> (4.2300000000000000-2.230000000000000) == 2.0000000000000001
[1] FALSE
> (4.2300000000000000-2.230000000000000) == 2.0000000000000003
[1] TRUE
> (4.2300000000000000-2.230000000000000) == 2.0000000000000004
[1] TRUE
> (4.2300000000000000-2.230000000000000) == 2.0000000000000005
[1] TRUE
> (4.2300000000000000-2.230000000000000) == 2.0000000000000006 <-- 3,5 I  
> can understand being true if rounding occurring, but 6?
[1] TRUE
> (4.2300000000000000-2.230000000000000) == 2.0000000000000007
[1] FALSE
> (4.2300000000000000-2.230000000000000) == 2.0000000000000008
[1] FALSE
> (4.2300000000000000-2.230000000000000) == 2.0000000000000009
[1] FALSE
> (4.2300000000000000-2.230000000000000) == 2.0000000000000010


This is an example of junk being added in the FPU
> formatC(a, digits=20)
[1] "2.0000000000000004441"

I don't know if this is just a formatC error when using more than 16  
decimal places or if this junk is what is stopping the equality from being  
true:

> formatC(a, digits=16)
[1] "                2"
> formatC(a, digits=17)  <-- 16 decimal places, 17 significant figures  
> shown
[1] "2.0000000000000004" <-- the problem is the 4 at the end

Obviously the bytes are divided between the exponent and mantissa in  
16-16bit share it seems, but this doesn't account for the 16th decimal  
place behaviour does it?

If any one has a work around or reason why this should occur it would be  
useful to know.

what I would like is to be able to do sums such as (2.3456 - 2 ) == 0.3456  
and get a sensible answer - any suggestions?  Currently the only way is  
for formatC the expression to a known number of decimal places - is there  
a better way?

Many thanks

Tom


-- 
Dr. Thomas McCallum
Systems Architect,
Level E Limited
ETTC, The King's Buildings
Mayfield Road,
Edinburgh EH9 3JL, UK
Work  +44 (0) 131 472 4813
Fax:  +44 (0) 131 472 4719
http://www.levelelimited.com
Email: tom at levelelimited.com

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