sub() and gsub() (PR#1826)
ripley@stats.ox.ac.uk
ripley@stats.ox.ac.uk
Tue, 23 Jul 2002 22:01:22 +0100 (BST)
Those are not blanks! You have character <A0> in there. less on your
email gives me
> x <- structure(c(1, 3, 4, 5), class = "factor",
+ .Label = c("1 ", "2 ", "3 ", "4<A0>", "5<A0>"))
> y <- as.character(x)
> y
[1] "1 " "3 " "4<A0>" "5<A0>"
> gsub(" ","",y)
[1] "1" "3" "4<A0>" "5<A0>"
which is correct.
Pilot error, I believe ....
On Tue, 23 Jul 2002 jerome@hivnet.ubc.ca wrote:
> Full_Name: Jerome Asselin
> Version: 1.5.1
> OS: linux redhat 7.2
> Submission from: (NULL) (142.103.173.179)
>
>
>
> gsub() return different answers depending on how the input
> variables were created. Here is an example of code that
> replicates the problem. The vectors y and yy appear to be
> the same, but gsub() doesn't return the same answer.
> It should remove all the blanks when I use the vector y,
> but it doesn't remove them all. I have also tested that
> the same problem occurs if sub() is used instead of gsub().
>
> x <- structure(c(1, 3, 4, 5), class = "factor",
> .Label = c("1 ", "2 ", "3 ", "4 ", "5 "))
> y <- as.character(x)
> y
> gsub(" ","",y)
>
> yy <- c("1 ","3 ","4 ","5 ")
> yy
> gsub(" ","",yy)
>
>
> Below is the output that I have when I execute those commands.
>
>
> > x <- structure(c(1, 3, 4, 5), class = "factor",
> + .Label = c("1 ", "2 ", "3 ", "4 ", "5 "))
> > y <- as.character(x)
> > y
> [1] "1 " "3 " "4 " "5 "
> > gsub(" ","",y)
> [1] "1" "3" "4 " "5 "
> >
> > yy <- c("1 ","3 ","4 ","5 ")
> > yy
> [1] "1 " "3 " "4 " "5 "
> > gsub(" ","",yy)
> [1] "1" "3" "4" "5"
>
>
>
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--
Brian D. Ripley, ripley@stats.ox.ac.uk
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
1 South Parks Road, +44 1865 272860 (secr)
Oxford OX1 3TG, UK Fax: +44 1865 272595
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