problem with qq( ) (PR#1729)
deepayansarkar@yahoo.com
deepayansarkar@yahoo.com
Mon, 8 Jul 2002 19:44:53 +0200 (MET DST)
--- ripley@stats.ox.ac.uk wrote:
> 1) This is a report on the lattice package, and we both need you to
> mention that and to give the version number of lattice that you used
> to be sure of beeing able to reproduce this.
>
> 2) It seems that the plots are actually correct, just the labels are
> wrong. You can correct that by specifying xlab and ylab in the call.
>
> 3) The error appears to be a typo:
>
> if (missing(ylab))
> ylab <- if (is.f.y)
> unique(levels(y))[y]
> else paste("y:", as.character(unique(levels(y)[[2]])))
>
> should be [2] for consistency.
Thanks, fixed for future releases.
> On Tue, 2 Jul 2002 Jarno.Tuimala@Helsinki.Fi wrote:
>
> > Full_Name: Jarno Tuimala
> > Version: 1.5.0
> > OS: Windows Nt
> > Submission from: (NULL) (193.166.1.21)
> >
> >
> > Running the following analysis gives as a result kukot vs. kisut.
> >
> > aikaero <- -27.5+5*(0:10)
> > frekvenssi.m <- c(0,1,15,37,53,45,23,18,4,1,1)
> > frekvenssi.n <- c(2,8,12,19,33,47,42,15,2,1,0)
> > win.graph()
> > aikaero <- rep(c(aikaero,aikaero), c(frekvenssi.m,frekvenssi.n))
> > a.ero <- data.frame(aikaero,
> > sukupuoli=rep(c("kukot","kisut"),
> > c(sum(frekvenssi.m),sum(frekvenssi.n))))
> > qq(sukupuoli ~ aikaero, data=a.ero)
> >
> > However, running the following analysis, gives miehet vs. miehet.
> >
> > aikaero <- -27.5+5*(0:10)
> > frekvenssi.m <- c(0,1,15,37,53,45,23,18,4,1,1)
> > frekvenssi.n <- c(2,8,12,19,33,47,42,15,2,1,0)
> > win.graph()
> > aikaero <- rep(c(aikaero,aikaero), c(frekvenssi.m,frekvenssi.n))
> > a.ero <- data.frame(aikaero,
> > sukupuoli=rep(c("miehet","naiset"),
> > c(sum(frekvenssi.m),sum(frekvenssi.n))))
> > qq(sukupuoli ~ aikaero, data=a.ero)
> >
> > This seems to happen everytime "sukupuoli" contains one variable name,
> which
> > starts with a letter "n". If both names start with "n" or other letters the
> > results is miehet vs naiset as expected.
> >
> > So this works fine:
> >
> > a.ero <- data.frame(aikaero,
> > sukupuoli=rep(c("nisset","naiset"),
> > c(sum(frekvenssi.m),sum(frekvenssi.n))))
> > qq(sukupuoli ~ aikaero, data=a.ero)
> >
> > And this also:
> >
> > a.ero <- data.frame(aikaero,
> > sukupuoli=rep(c("miehet","maiset"),
> > c(sum(frekvenssi.m),sum(frekvenssi.n))))
> > qq(sukupuoli ~ aikaero, data=a.ero)
> >
> > Where's the problem?
> >
> >
> >
>
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>
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> >
>
> --
> Brian D. Ripley, ripley@stats.ox.ac.uk
> Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
> University of Oxford, Tel: +44 1865 272861 (self)
> 1 South Parks Road, +44 1865 272860 (secr)
> Oxford OX1 3TG, UK Fax: +44 1865 272595
>
>
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