[Rd] labels returned by cut() when include.lowest=T (PR#1263)

[stephen@cogsci.ed.ac.uk]

Full_Name: Stephen Eglen
Version: 1.4
OS: Redhat Linux 7.1
Submission from: (NULL) (128.252.204.36)


I think the brackets in the levels of cut() are slightly incorrect when
include.lowest is TRUE.

For example:

> table(cut( c(1,4), include.lowest=T, right=F, breaks=c(1,2,3,4)))

[1,2) [2,3) [3,4) 
    1     0     1 

I think the last range in this case should be [3,4].  A similar
problem exists for the first range when right=T.

Here is a possible patch against 1.4.0, which on the above example gives:
[1,2) [2,3) [3,4] 
    1     0     1 

Stephen

*** /tmp/cut.R.orig716Cri	Mon Jan 14 22:58:12 2002
--- /tmp/cut.R716P1o	Mon Jan 14 22:58:12 2002
***************
*** 25,30 ****
--- 25,35 ----
  			 ch.br[-nb], ",", ch.br[-1],
  			 if(right)"]" else ")", sep='')
  	    else paste("Range", 1:(nb - 1),sep="_")
+         if (ok && include.lowest)
+           if (right)
+             labels[1] <- sub("\\(", "\\[", labels[1])
+           else
+             labels[nb-1] <- sub(")", "]", labels[nb-1])
      } else if (is.logical(labels) && !labels)
          codes.only <- TRUE
      else if (length(labels) != nb-1)




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