[Rd] factors in data.frames (PR#835)

[james.lindsey@luc.ac.be]

The following seems to be a contradiction:

> df <- data.frame(x=gl(2,1,10))
> df[,1]
 [1] 1 2 1 2 1 2 1 2 1 2
Levels:  1 2 
> df[,1,drop=F]
   x
1  1
2  2
3  1
4  2
5  1
6  2
7  1
8  2
9  1
10 2
> is.factor(df[,1,drop=F])
[1] FALSE
> is.factor(df[,1])
[1] TRUE

with R1.2.1 both MS Windows and Intel RH5.2 versions.
 Jim

-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-
r-devel mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html
Send "info", "help", or "[un]subscribe"
(in the "body", not the subject !)  To: r-devel-request@stat.math.ethz.ch
_._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._