[Rd] all.equal.list() sometimes fails with unnamed and named components (PR#674)
Peter Dalgaard BSA
p.dalgaard@biostat.ku.dk
03 Oct 2000 18:05:50 +0200
Kurt Hornik <Kurt.Hornik@ci.tuwien.ac.at> writes:
> Maybe we should change this as follows: if either of the two lists has
> names, work though the named components. Warn about the ones not
> present in both. Compare the ones present in both. Then get rid of all
> named components and compare what is left in positional order.
>
> As I said, I am not sure that this is really what we want.
>
> Comments?
I think you might be right, and also that this is an easy thing to
implement. Then we'd have
all.equal(list(a=1,b=2,3,4),list(3,b=2,4,a=1)) == TRUE
Right?
However, BigBrother has
> all.equal(list(a=1,b=2,3,4),list(3,b=2,4,a=1))
[1] "Names: 2 string mismatches"
attr(, "continue"):
[1] T
> all.equal(list(a=1,b=2,3,4), list(a=1,b=2,4,3))
[1] T
..which does look like a "compatible bug"
Hmm. Maybe one wants positional matching in any case? But then, what
is the named-component extraction about??
--
O__ ---- Peter Dalgaard Blegdamsvej 3
c/ /'_ --- Dept. of Biostatistics 2200 Cph. N
(*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918
~~~~~~~~~~ - (p.dalgaard@biostat.ku.dk) FAX: (+45) 35327907
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