set functions
Jonathan Rougier
J.C.Rougier@durham.ac.uk
Tue, 4 Jan 2000 16:45:12 +0000 (GMT)
On 4 Jan 2000, Peter Dalgaard BSA wrote:
> > length(setdiff(1:4, 1:5))==0 # is TRUE
> > equiv(1:4, 1:5) # clearly FALSE
>
> Argh. I was thinking of the symmetric set difference. So you'd need
> setdiff(y,x)==0 & setdiff(x,y)==0 which is obviously only half as fast
> as twice as fast....
>
> However:
>
> equiv<-function(x,y)
> length(x<-unique(x))==length(y<-unique(y)) &&
> all(sort(x)==sort(y))
Yes, I wondered about that, and also about
"equiv" <-
function(x, y) {
x <- unique(x)
y <- unique(y)
length(x)==length(y) && all(1:length(y) == sort(match(x, y, 0)))
}
but I thought that perhaps a sort would be more expensive than a second
call to match, and more so for two sorts. Cheers, Jonathan.
Jonathan Rougier Science Laboratories
Department of Mathematical Sciences South Road
University of Durham Durham DH1 3LE
"[B]egin upon the precept ... that the things we see are to be
weighed in the scale with what we know" (Meredith, 1879, The Egoist)
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