typeof ( substitute(expression(),..) ) -- musings
Martin Maechler
Martin Maechler <maechler@stat.math.ethz.ch>
Tue, 29 Jun 1999 18:27:15 +0200
[Relates to math text / normal text mixing in plots ..]
Peter, I knew you'd know the answer quickly...
Anyway, one needs to be somewhat careful here [R version pre 0.64.2]:
typeof(print( e1 <- expression(a + b))) # expression
typeof(print(se1 <- substitute(expression(a + b), list(a = 1)))) # language
length(e1) # == 1
length(se1)# == 2
text.e <- function(x,y,e) {
text(x,y,paste(deparse(substitute(e)),": "),adj=c(1,0))
text(x,y,e, adj=0)
}
plot(1,type="n", axes= F)
text.e(1,1.4, e1); text.e(1,1.3, se1); text.e(1,1.2, se1[[2]])
Which shows that you can't use the result of `substitute' directly, but
rather the 2nd element [[which is *still* not an expression !!]]
This is all +- S-plus (3.4) compatible
{{some details are NOT compatible; e.g.
as.expression(se1[[2]])
gives `what you expect' in R, but not in S-plus 3.4 or 5.0r3
}}
e1 is an expression whereas
se1 is a call (aka "language" in R).
----
Is this documented anywhere? [blue book; language reference; ?? ]
Martin
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