as.list

[Kjetil Halvorsen]

I don't understand the behavior of "as.list"
(really as.list.default) on arguments which
are expressions. An artificial example:

> as.list(expression( x <- 1, y <- 2))
[[1]]
<-

[[2]]
<-

as.list.default contains the following code:

 if (is.expression(x)) {
        l <- vector("list")
        for (sub in x) l <- c(l, sub[[1]])

--- why the sub[[1]] part?

eliminating the [[1]], I get:

> my.as.list(expression( x <- 1, y <- 2))
[[1]]
x <- 1

[[2]]
y <- 2


Kjetil Halvorsen
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