as.list
Kjetil Halvorsen
khal@alumni.uv.es
Tue, 24 Nov 1998 17:05:47 +0100
I don't understand the behavior of "as.list"
(really as.list.default) on arguments which
are expressions. An artificial example:
> as.list(expression( x <- 1, y <- 2))
[[1]]
<-
[[2]]
<-
as.list.default contains the following code:
if (is.expression(x)) {
l <- vector("list")
for (sub in x) l <- c(l, sub[[1]])
--- why the sub[[1]] part?
eliminating the [[1]], I get:
> my.as.list(expression( x <- 1, y <- 2))
[[1]]
x <- 1
[[2]]
y <- 2
Kjetil Halvorsen
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