On Thu, Aug 20, 2009 at 4:24 PM, Peng Yu <pengyu.ut@gmail.com> wrote:

> Hi,
>
> I run the following command. But it only gives the file names. I am
> wondering if there is a way to get the filename along with the
> directory name, i.e., 'data/ki10923.CEL', etc.
>
> Regards,
> Peng
>
> > list.celfiles('data/')
>  [1] "ki10923.CEL" "ki10924.CEL" "ki10925.CEL" "ki10926.CEL" "ki10928.CEL"
>  [6] "wt10921.CEL" "wt10922.CEL" "wt10927.CEL" "wt10930.CEL" "wt10980.CEL"
>

Hi, Peng.

Reading the help for list.celfiles(), it suggests that all arguments are
passed along to the list.files().  Reading the help for list.files()
suggests that including full.names=TRUE will return the information you
want.

Sean

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