[BioC] log Fold Change
michael watson (IAH-C)
michael.watson at bbsrc.ac.uk
Tue Mar 16 22:39:09 CET 2010
Assuming your design matrix is c(1,1,-1,-1) then the latter two M values are multiplied by -1:
> mean(c(-1.1907,-1.00507,-0.68244023,-0.815401))
[1] -0.9234028
________________________________________
From: bioconductor-bounces at stat.math.ethz.ch [bioconductor-bounces at stat.math.ethz.ch] On Behalf Of Jay [jboddu at uiuc.edu]
Sent: 16 March 2010 21:29
To: bioconductor at stat.math.ethz.ch
Subject: [BioC] log Fold Change
Hi All:
Even after going through hand full of posts on log fold change, I could not
figure out how exactly it is calculated in LIMMA.
Please see following example.
Arrays 3 and 4 are dye swaps for arrays 1 and 2 (Arrays 1 and 2 are rep 1
and rep 2).
For Gene 1;
The M values are,
1
2
3
4
-1.1907
-1.00507
0.68244023
0.815401
And the A values are,
1
2
3
4
7.693117
6.218356
7.59435237
6.671801
After computing the linear model fit the output is,
logFC
AveExpr
t
P.Value
adj.P.Val
B
-0.9234
7.044406
-8.0598372
0.000229
0.00306
0.868682
I am wondering how the logFC (-0.9234) is gotten.
LIMMA user guide says M values are simply the log2 fold changes between
conditions.
Any help is appreciated.
Thanks
Jay
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