[BioC] 2x2 factorial loop without common reference (pool)
Naomi Altman
naomi at stat.psu.edu
Sun Apr 23 21:14:46 CEST 2006
I would use single channel analysis for
this. The only problem is that Limma allows only
1 level of random effects. Hence, you will need to average the dye-swaps.
Anyways with single channel analysis, you have a
balanced incomplete block design with factorial
treatments, and the analysis is much simplified.
--Naomi
At 01:41 PM 4/23/2006, francois fauteux wrote:
>Hi;
>
>We are doing an experiment with agilent 44K (3 biological reps,
>complete dye-swap):
>
>a - control
>b - treatment 1
>c - treatment 2
>d - treatment 1 + treatment 2
>
>and I would like to output evidence of the interaction between two
>treatments and effect on gene expression.
>
>24 chips:
>
>SlideNumber Cy3 Cy5
>1 a1 b1
>2 a2 b2
>3 a3 b3
>4 b1 a1
>5 b2 a2
>6 b3 a3
>7 a1 c1
>8 a2 c2
>9 a3 c3
>10 c1 a1
>11 c2 a2
>12 c3 a3
>13 b1 d1
>14 b2 d2
>15 b3 d3
>16 d1 b1
>17 d2 b2
>18 d3 b3
>19 c1 d1
>20 c2 d2
>21 c3 d3
>22 d1 c1
>23 d2 c2
>24 d3 c3
>
>I've done several tests with limma to isolate significant results in
>the following:
>1- a vs b;
>2- a vs c;
>3- b bs d;
>4- c vs d;
>
>with this "targets.txt":
>
>SlideNumber Cy3 Cy5
>1 a b
>2 a b
>3 a b
>4 b a
>5 b a
>6 b a
>7 a c
>8 a c
>9 a c
>10 c a
>11 c a
>12 c a
>13 b d
>14 b d
>15 b d
>16 d b
>17 d b
>18 d b
>19 c d
>20 c d
>21 c d
>22 d c
>23 d c
>24 d c
>
>First option:
>
> > f <- paste(targets$Cy3, targets$Cy5, sep = ".")
> > f <- factor(f, levels = c("a.b", "b.a",
> "a.c", "c.a", "b.d", "d.a", "c.d", "d.a"))
> > design1 <- model.matrix(~0 + f)
>
> > design
> a.b b.a a.c c.a b.d d.b c.d d.c
>1 1 0 0 0 0 0 0 0
>2 1 0 0 0 0 0 0 0
>3 1 0 0 0 0 0 0 0
>4 0 1 0 0 0 0 0 0
>5 0 1 0 0 0 0 0 0
>6 0 1 0 0 0 0 0 0
>7 0 0 1 0 0 0 0 0
>8 0 0 1 0 0 0 0 0
>9 0 0 1 0 0 0 0 0
>10 0 0 0 1 0 0 0 0
>11 0 0 0 1 0 0 0 0
>12 0 0 0 1 0 0 0 0
>13 0 0 0 0 1 0 0 0
>14 0 0 0 0 1 0 0 0
>15 0 0 0 0 1 0 0 0
>16 0 0 0 0 0 1 0 0
>17 0 0 0 0 0 1 0 0
>18 0 0 0 0 0 1 0 0
>19 0 0 0 0 0 0 1 0
>20 0 0 0 0 0 0 1 0
>21 0 0 0 0 0 0 1 0
>22 0 0 0 0 0 0 0 1
>23 0 0 0 0 0 0 0 1
>24 0 0 0 0 0 0 0 1
>
>This gives significant results for each one of the "levels" but does
>not take into account the dye-swap (i.e "a.b" and "b.a" are considered
>independent).
>
>Other tested option is:
> > design2 <- modelMatrix(targets,ref="a")
>
> > design
> p s sp
>ab1 0 1 0
>ab2 0 1 0
>ab3 0 1 0
>ba1 0 -1 0
>ba2 0 -1 0
>ba3 0 -1 0
>ac1 1 0 0
>ac2 1 0 0
>ac3 1 0 0
>ca1 -1 0 0
>ca2 -1 0 0
>ca3 -1 0 0
>bd1 0 -1 1
>bd2 0 -1 1
>bd3 0 -1 1
>db1 0 1 -1
>db2 0 1 -1
>db3 0 1 -1
>cd1 -1 0 1
>cd2 -1 0 1
>cd3 -1 0 1
>dc1 1 0 -1
>dc2 1 0 -1
>dc3 1 0 -1
>
>This gives results for "b" effect, "c" effect, and "d" effect.
>However, I could'nt get results for the 4 comparisons of interest
>(even though the matrix is coherent).
>
>Questions:
>
>1 - What would be the best option (design and operations) to get to
>contrasts of interest considering that the experiment has a 4
>treatments in a factorial design without common reference (a vs b, a
>vs c, b vs d, c vs d) and taking into account the dye-effect;
>
>2- Is this method (4 contrasts) the best one considering that
>treatment "d" is a combination of treatments "b" and "c" (factorial
>type design). How could one directly get to identify genes
>differentially expressed due to the interaction between treatment "b"
>and treatment "c" (i.e effect of "d" over "b" and "c").
>
>In Limma Users Guide and elsewhere on this forum, I could not find a
>clear description of how this type of analysis should be performed,
>even though it is a simple design (i.e 2X2 factorial without a common
>reference - two color arrays - complete dye swap).
>
>Thanks for your time, best regards.
>
>François Fauteux
>Étudiant à la maîtrise en biologie végétale
>Centre de recherche en horticulture
>Université Laval
>francois.fauteux at gmail.com
>
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Naomi S. Altman 814-865-3791 (voice)
Associate Professor
Dept. of Statistics 814-863-7114 (fax)
Penn State University 814-865-1348 (Statistics)
University Park, PA 16802-2111
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