findInterval {base}  R Documentation 
Given a vector of nondecreasing breakpoints in vec
, find the
interval containing each element of x
; i.e., if
i < findInterval(x,v)
, for each index j
in x
v[i[j]] ≤ x[j] < v[i[j] + 1]
where v[0] :=  Inf,
v[N+1] := + Inf, and N < length(v)
.
At the two boundaries, the returned index may differ by 1, depending
on the optional arguments rightmost.closed
and all.inside
.
findInterval(x, vec, rightmost.closed = FALSE, all.inside = FALSE)
x 
numeric. 
vec 
numeric, sorted (weakly) increasingly, of length 
rightmost.closed 
logical; if true, the rightmost interval,

all.inside 
logical; if true, the returned indices are coerced
into 
The function findInterval
finds the index of one vector x
in
another, vec
, where the latter must be nondecreasing. Where
this is trivial, equivalent to apply( outer(x, vec, ">="), 1, sum)
,
as a matter of fact, the internal algorithm uses interval search
ensuring O(n * log(N)) complexity where
n < length(x)
(and N < length(vec)
). For (almost)
sorted x
, it will be even faster, basically O(n).
This is the same computation as for the empirical distribution
function, and indeed, findInterval(t, sort(X))
is
identical to n * Fn(t;
X[1],..,X[n]) where Fn is the empirical distribution
function of X[1],..,X[n].
When rightmost.closed = TRUE
, the result for x[j] = vec[N]
( = max(vec)), is N  1
as for all other
values in the last interval.
vector of length length(x)
with values in 0:N
(and
NA
) where N < length(vec)
, or values coerced to
1:(N1)
if and only if all.inside = TRUE
(equivalently coercing all
x values inside the intervals). Note that NA
s are
propagated from x
, and Inf
values are allowed in
both x
and vec
.
Martin Maechler
approx(*, method = "constant")
which is a
generalization of findInterval()
, ecdf
for
computing the empirical distribution function which is (up to a factor
of n) also basically the same as findInterval(.)
.
x < 2:18 v < c(5, 10, 15) # create two bins [5,10) and [10,15) cbind(x, findInterval(x, v)) N < 100 X < sort(round(stats::rt(N, df = 2), 2)) tt < c(100, seq(2, 2, len = 201), +100) it < findInterval(tt, X) tt[it < 1  it >= N] # only first and last are outside range(X)